2=(11/(2x-1))+(-5/(2x-1)^2)

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Solution for 2=(11/(2x-1))+(-5/(2x-1)^2) equation:


D( x )

2*x-1 = 0

(2*x-1)^2 = 0

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

(2*x-1)^2 = 0

(2*x-1)^2 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x in (-oo:1/2) U (1/2:+oo)

2 = 11/(2*x-1)-5/((2*x-1)^2) // - 11/(2*x-1)-5/((2*x-1)^2)

2-(11/(2*x-1))-(-5/((2*x-1)^2)) = 0

5*(2*x-1)^-2-11*(2*x-1)^-1+2 = 0

5/((2*x-1)^2)-11/(2*x-1)+2 = 0

(-11*(2*x-1))/((2*x-1)^2)+5/((2*x-1)^2)+(2*(2*x-1)^2)/((2*x-1)^2) = 0

2*(2*x-1)^2-11*(2*x-1)+5 = 0

8*x^2-22*x-8*x+2+16 = 0

8*x^2-30*x+18 = 0

8*x^2-30*x+18 = 0

2*(4*x^2-15*x+9) = 0

4*x^2-15*x+9 = 0

DELTA = (-15)^2-(4*4*9)

DELTA = 81

DELTA > 0

x = (81^(1/2)+15)/(2*4) or x = (15-81^(1/2))/(2*4)

x = 3 or x = 3/4

2*(x-3/4)*(x-3) = 0

(2*(x-3/4)*(x-3))/((2*x-1)^2) = 0

(2*(x-3/4)*(x-3))/((2*x-1)^2) = 0 // * (2*x-1)^2

2*(x-3/4)*(x-3) = 0

( x-3/4 )

x-3/4 = 0 // + 3/4

x = 3/4

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 3/4, 3 }

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